Three-phase power formulas
kVA = √3 × VL-L × I ÷ 1000
kW = kVA × PF = √3 × VL-L × I × PF ÷ 1000
I = kW × 1000 ÷ (√3 × VL-L × PF)
√3 ≈ 1.732. VL-L is the voltage measured between any two phases: 208, 240, 480 or 600 V on common North American systems. I is the current in each line. These formulas assume the load is balanced, meaning roughly equal current on all three phases. That is true for motors, most HVAC equipment and properly laid out panels.
Worked examples
1. A 208 V panel at 100 A
kVA = 1.732 × 208 × 100 ÷ 1000 = 36.0 kVA
kW at PF 0.9 = 36.0 × 0.9 = 32.4 kW
That is the most this feeder can deliver at full load. A 100 A, 120/208 V panel serves about 36 kVA.
2. The same current at 480 V
kVA = 1.732 × 480 × 100 ÷ 1000 = 83.1 kVA
The same 100 A carries 2.3 times the power at 480 V. That is why commercial and industrial buildings distribute at 480 V and step down to 208 V only where receptacles and lighting need it.
3. Current for a 50 kW load
A 50 kW process load at 480 V with a power factor of 0.85:
I = 50,000 ÷ (1.732 × 480 × 0.85) = 50,000 ÷ 706.7 ≈ 70.8 A
If the load is continuous, conductors must be rated at least 125% of that, 88.5 A. The wire size calculator gives 3 AWG copper at 75 °C (100 A). For long feeders, check the 3 phase voltage drop too.
Single phase vs three phase
A single-phase load draws power in pulses that drop to zero 120 times a second. Three phases overlap so total power is constant, which lets motors run smoothly and makes three-phase conductors more efficient: three wires carry √3 times the power of two wires at the same voltage and current. For single-phase loads, use the amps to watts calculator.
Common three-phase voltages
| System | Line-to-line | Line-to-neutral | Typical use |
|---|---|---|---|
| 120/208 V wye | 208 V | 120 V | Commercial receptacles, lighting, small RTUs |
| 120/240 V high-leg delta | 240 V | 120 V (208 V high leg) | Older shops and light industrial |
| 277/480 V wye | 480 V | 277 V | US commercial and industrial |
| 347/600 V wye | 600 V | 347 V | Canadian commercial and industrial |
Power factor
Power factor is the ratio of real power (kW) to apparent power (kVA). Resistive heating has a PF of 1. Induction motors typically run around 0.85 at full load and much lower when lightly loaded. Equipment and conductors must carry the full kVA current, which is why utilities may charge industrial customers for low power factor, and why capacitor banks or drives are used to correct it.
Unbalanced loads
When phase currents differ, the simple formula is only an estimate. Calculate each phase separately with line-to-neutral voltage (kVA per phase = VL-N × I ÷ 1000) and add the three results. Size the feeder for the most heavily loaded phase.